But now, the squares and straight lines you focused on in algebra are transitioning to curves and circles in trigonometry!
PRESENTING: THE POLAR GRAPH!
Polar graphs have circles and angles, so instead of the normal x or y-axis, these use DEGREES and
RADII. The coordination is as follows:
(radius, Θ) or (Θ, radius)
The rule for plotting points is very simple:
you can either
-turn to the direction and move radius units towards it or
-move radius units and walk to the direction
EXAMPLES:
RADII. The coordination is as follows:
(radius, Θ) or (Θ, radius)
The rule for plotting points is very simple:
you can either
-turn to the direction and move radius units towards it or
-move radius units and walk to the direction
EXAMPLES:
EXAMPLE: Plotting Points
Plot the following points: (5, 330º), (2, 180º), and (-45º, 2)
·
(2,180°): Move
forward 5, turn 330 degrees
·
(-45°, 2): Move
forward 2, turn negative 45 degrees
·
(2,180°): Turn 180
degrees, move forward 2
**Note, there is no one exactly way to plot these points, you
can choose any method you like to get to the destination. Imagine a Cartesian graph on top of a Polar graph. Where would the point (4, 60°) be on the Cartesian graph?
HINT: Try imagining the 0° and 90° as the x and y-axis.
To find the points on a Cartesian plane, we must find how many units, a,
it moves on the x-axis, and how many b-units are moved on the y-axis.
EXAMPLE: Polar >> Rectangular
Where's the polar point (4, 60°) on a Cartesian graph?
<<<< Here's what we have so far
Because this is a right triangle, we can now use our trig to solve for the
triangle's sides!doesn't this look familiar *cough* vectors *cough*
1) sin(60°) = b/4 1) cos(60°) = a/4
2) 4sin(60°) = b 2) 4cos(60°) = a
3) 4(√3/2) = b 3) 4(1/2) = a
4) 2√3 = b 4) 2 = a
The polar point (4, 60°) would be exactly where (2, 2√3) would be on a Cartesian graph.
Now, where would (3, 4) be on a polar graph?
EXAMPLE: Rectangular >> Polar
Because this is a right triangle, we can now use our trig to solve for the angle (Ɵ) and radius (r)!
1) tan Ɵ = 4/3 1) r² = 3² + 4²
2) Ɵ = tan‾ ¹(4/3) 2) r² = 9 + 16
3) Ɵ = 53.13° 3) r² = 25
4) r = 5
The coordinate point (3,4) would be exactly
(5, 53.13°) on a polar graph. That's it!
-TrigInADay
HINT: Try imagining the 0° and 90° as the x and y-axis.
To find the points on a Cartesian plane, we must find how many units, a,
it moves on the x-axis, and how many b-units are moved on the y-axis.
EXAMPLE: Polar >> Rectangular
Where's the polar point (4, 60°) on a Cartesian graph?
<<<< Here's what we have so far
Because this is a right triangle, we can now use our trig to solve for the
triangle's sides!
1) sin(60°) = b/4 1) cos(60°) = a/4
2) 4sin(60°) = b 2) 4cos(60°) = a
3) 4(√3/2) = b 3) 4(1/2) = a
4) 2√3 = b 4) 2 = a
The polar point (4, 60°) would be exactly where (2, 2√3) would be on a Cartesian graph.
Now, where would (3, 4) be on a polar graph?
EXAMPLE: Rectangular >> Polar
Because this is a right triangle, we can now use our trig to solve for the angle (Ɵ) and radius (r)!
1) tan Ɵ = 4/3 1) r² = 3² + 4²
2) Ɵ = tan‾ ¹(4/3) 2) r² = 9 + 16
3) Ɵ = 53.13° 3) r² = 25
4) r = 5
The coordinate point (3,4) would be exactly
(5, 53.13°) on a polar graph. That's it!
-TrigInADay
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